If I=\int \frac{d x}{ \sin (x-a) \sin (x-b)}, then I is given by

Correct Answer is : 1sin(b−a)log|sin(x−b)sin(x−a)|+c, where c is a constant of integration.

\frac{1}{ \sin (b-a)} \log | \sin (x-a) \sin (x-b)|+c, where c is a constant of integration.

\log {| \frac{ \sin (x-a)}{ \sin (x-b)} |}+c, where c is a constant of integration.

\frac{1}{ \sin (b-a)} \log {| \frac{ \sin (x-a)}{ \sin (x-b)} |}+c, where c is a constant of integration.

\frac{1}{ \sin (b-a)} \log {| \frac{ \sin (x-b)}{ \sin (x-a)} |}+c, where c is a constant of integration.

MHTCET 14 May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 97 of 150

Marks: +1, -0

If I=∫‌

sin‌(x−a)‌sin‌(x−b)

, then I is given by

‌
1
sin‌(b−a)
‌log|sin‌(x−a)‌sin‌(x−b)|+c, where c is a constant of integration.
log‌|‌
sin‌(x−a)
sin‌(x−b)
|+c, where c is a constant of integration.
‌
1
sin‌(b−a)
‌log‌|‌
sin‌(x−a)
sin‌(x−b)
|+c, where c is a constant of integration.
‌
1
sin‌(b−a)
‌log‌|‌
sin‌(x−b)
sin‌(x−a)
|+c, where c is a constant of integration.

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