The kinetic energy of a simple harmonic oscillator of mass 'm' is given by {k}= {k}_{0} \cos ^{2} \\omega t. The displacement equation is given by

Correct Answer is : √2k0mω2sinωt

\sqrt{ {2 \\omega^{2}/{m k_{0}}} \sin \\omega t

\sqrt{ \frac{2 k_0}{m \\omega}} \sin \\omega t

\sqrt{ \frac{m k_0}{ \\omega^2}} \sin \\omega t

\sqrt{ \frac{2 k_0}{m \\omega^2}} \sin \\omega t

NEET 2019 Model Question Paper 3

Question : 100 of 180

Marks: +1, -0

The kinetic energy of a simple harmonic oscillator of mass 'm' is given by k=k0cos2ωt. The displacement equation is given by

Go to Question:

Prev Question

Next Question