\PhCOOH+\C_2\H_5\O^{18}\H\stackrel{\conc.\H_2\SO_4}{––––––––▸}\A (major product) A is

Correct Answer is : PH−C∥O−18OC2H5

\PH-\C_{\parallel}_{\O}-\OC_2\H_5

\PH-\C_{\parallel}_{\O}-\O^{18}\C_2\H_5

\PH-\C_{\parallel}_{\O}_{18}-\OC_2\H_5

\PH-\C_{\parallel}_{\O}_{18}-\O^{18}\C_2\H_5

NEET 2021 Model Test Paper 3

Question : 48 of 180

Marks: +1, -0

PhCOOH+C2H5

conc.H2SO4

––––––––▸

A
(major product) A is

Go to Question:

Prev Question

Next Question