NEET 2021 Physics and Chemistry

Given that :
Mass of ball = 0.15 kg
Height from which ball is dropped = 10 m
Impulse,

→

I

= Change in linear momentum =Δ

→

P

=

→

Pf

−

→

Pi

Velocity of ball at ground (v)=√2gh
=√2×10×10=10√2m∕s

→

I

=0.15×10√2(−

^

j

)−0.15×10√2(

^

j

)

→

I

=2×0.15×10√2(−

^

j

)=4.2(−

^

j

)
⇒ magnitude of impulse =4.2kgm∕s