Consider the reaction: N_{2}(g)+3H_{2}(g)\to2NH_{3}(g) The equality relationship between \frac{d[NH_3]}{dt} and -\frac{d[H_2]}{dt} is (2006)

Correct Answer is : +d[NH3]dt=−23d[H2]dt

\frac{d[NH_3]}{dt}=-\frac{d[H_2]}{dt}

\frac{d[NH_3]}{dt}=-1/3\frac{d[H_2]}{dt}

+\frac{d[NH_3]}{dt}=-2/3\frac{d[H_2]}{dt}

+\frac{d[NH_3]}{dt}=-3/2\frac{d[H_2]}{dt}

Class 12 NEET Chemistry Chemical Kinetics Questions

Question : 54 of 75

Marks: +1, -0

Consider the reaction: N2(g)+3H2(g)→2NH3(g) The equality relationship between

d[NH3]

and −

d[H2]

(2006)

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