Class 12 NEET Chemistry Chemical Kinetics Questions

For the reaction, 2A+B2⇌2AB,
Rate ∝[A]x[B2]y.
On substituting the given data, we get
From experiment 1
1.6×10−4∝[0.50]x[0.50]y ...(i)
From experiment 2 ,
3.2×10−4∝[0.50]x[1.00]y...(ii)
From experiment 3 ,
3.2×10−4∝[1.00]x[1.00]y ...(iii)
On dividing equation (iii) by (ii), we get,
1=[

1.00

0.50

]x ⇒1=2x ⇒20=2x⇒x=0
Now, divide equation (ii) by equation (i) we get,
2=[

1.00

0.50

]y ⇒2=2y⇒y=1
Thus rate equation is :
Rate =k[A]0[B2]1=k[B2]