CH_3-C_{|↙{CH_3}}H-CH-CH_2\stackrel{(CH_3COO)_2Hg}{–––––––––––>}_{H_2O}A\stackrel{NaBH_4}{––––––––>}_{OH^{-}}B B is

Correct Answer is : CH3−C|CH3H−COH|H−CH3

CH_3-C_{|↙{CH_3}}H-CH^{|↖{OH}}-CH_3

CH_3-C^{|↖{OH}}_{|↙{CH_3}}-CH_2-{C}_{|↙{OH}}H_2