Class 12 NEET Physics Atoms and Nuclei Questions Part 2

The wavelength of the first line of lyman series for hydrogen atom is

1

λ

=R[

1

12

−

1

22

]
The wavelength of the second line of Balmer series for hydrogen like ion is

1

λ′

=Z2R[

1

22

−

1

42

]
According to question, λ=λ′
⇒R[

1

12

−

1

22

]=Z2R[

1

22

−

1

42

]
or

3

4

=

3Z2

16

or z2=4 or Z=2