Class 11 NEET Physics Laws of Motion Questions

Mass of bullet (m1)=200‌gm =0.2‌kg
speed of bullet (v1)=5m∕sec.
and mass of gun (m2)=1‌kg.
Before firing, total momentum is zero.
∴ After firing total momentum is m1v1+m2v2
From the law of conservation of momentum
m1v1+m2v2=0
or v2=

−m1v1

m2

=

−0.2×5

1

=−1m∕s