The position vector of a particle is \overrightarrow{r}=(a \cos \\omega t) \stackrel{\^}{i}+(a \sin \\omega t) \stackrel{\^}{j}. The velocity of the particle is (1995)

Correct Answer is : perpendicular to the position vector.

parallel to the position vector

perpendicular to the position vector.

Class 11 NEET Physics Motion in a Plane Questions

Question : 63 of 74

Marks: +1, -0

The position vector of a particle is

→

=(a‌cos‌ω‌t)

+(a‌sin‌ω‌t)

. The velocity of the particle is

(1995)

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