Class 11 NEET Physics Motion in a Plane Questions

For the given velocity of projection u, the horizontal range is the same for the angle of projection θ and 90°−θ
Horizontal range R=

u2‌sin‌2‌θ

g

∴ For body A,RA=

u2‌sin(2×30°)

g

=

u2‌sin‌60°

g

For bodyB,RB=

u2‌sin(2×60°)

g

RB=

u2‌sin‌120°

g

=

u2‌sin(180°−60°)

g

=

u2‌sin‌60°

g

The range is the same whether the angle is theta or 90°−θ
∴ The ratio of ranges is 1: 1