The phase difference between two waves, represented by y_{1}=10^{-6} \sin [100 t+(x / 50) +0.5 ] {m} y_{2}=10^{-6} \cos [100 t+(x / 50)] {m} where x is expressed in metres and t is expressed in seconds, is approximately. (2004)

Correct Answer is : 1.07 radians

Class 11 NEET Physics Waves Questions Questions

Question : 54 of 94

Marks: +1, -0

The phase difference between two waves, represented by
y1=10−6‌sin[100t+(

)+0.5]‌m
y2=10−6‌cos[100t+(

)]‌m
where x is expressed in metres and t is expressed in seconds, is approximately.

(2004)

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