If a wave travelling in positive {x}-direction with {A}=0.2 {m} \/ {s}, velocity =360 {m} \/ {s} and \lambda=60 {m}, then correct expression for the wave is: (2002)

Correct Answer is : y=0.2sin[2π(6t−x60)]

y=0.2 \sin [2 \\pi(6 t+ \frac{x}{60} ) ]

y=0.2 \sin [ \\pi(6 t+ \frac{x}{60} ) ]

y=0.2 \sin [2 \\pi(6 t- \frac{x}{60} ) ]

y=0.2 \sin [ \\pi(6 t- \frac{x}{60} ) ]

Class 11 NEET Physics Waves Questions Questions

Question : 58 of 94

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If a wave travelling in positive x-direction with A=0.2m∕s, velocity =360m∕s and λ=60m, then correct expression for the wave is:

(2002)

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