NIMCET 2009 Question Paper with solutions

Question : 41 of 120

Marks: +1, -0

Bala had three sons. He had some chocolates which he distributed among them. To his eldest son, he gave 3 chocolates more than half the number of chocolates with him. To his second eldest son, he gave 4 chocolates more than one-third of the remaining number of chocolates with him. To his youngest son, he gave 4 chocolates more than one-fourth of the remaining number of chocolates with him. He was left with 11 chocolates. How many chocolates did he initially have?

Validate

Solution:

Let

x

be the number of chocolates initially Bala has.
Then,

\;{x}/{2}+3+\;{1}/{3}(\;{x}/{2}-3)+4+\;{1}/{4}[\;{x}/{3}-6]+4+11=x

⇒ \;\; \;{3 x}/{4}+\;{39}/{2}=x ⇒ \;{x}/{4}=\;{39}/{2}

⇒ \;\; x=\;{39 × 4}/{2}

⇒ \;\; x=78

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