NIMCET 2009 Question Paper with solutions

Question : 48 of 120

Marks: +1, -0

Sum of all three digit numbers (no digit being zero) having the property that all digits are perfect squares is

Solution:

Digits being perfect square and non-zero include 1,4 and

9 .

At each place digit. appear

2 !=2

times, so sum of all the three digit numbers

=(1+4+9) × 2 !(111)

=28(111)=3108

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