NIMCET 2009 Question Paper with solutions

Question : 57 of 120

Marks: +1, -0

The remainder when

x=1 !+2 !+3 !+\ldots+100 !

is divided by 240 is

Solution:

6 !=720

, so numbers from

6 !

onwards is divisible by

240 .

Hence, remainder is

1 !+2 !+31+4 !+5 !

=1+2+b+24+120=153

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