NIMCET 2015 Question Paper with solutions

61,52,63, 94?
The number formed by reversing the digit of each number of the sequence is square of consecutive natural numbers starting from 4. See how
$61...16=4^2$
$52....25=5^2$
$63....36=6^2$
$94....49=7^2$
Therefore, the required number $=8^2=64=46$