NIMCET 2018 Question Paper with solutions

First number divisible by 3 between 100 and 200 = 102
Last number divisible by 3 between 100 and 200 = 198 Total numbers divisible by 3 between 100 and 200 = 33 Out of which 105, 126, 147, 168 and 189 are divisible by 7 and from remaining numbers 102, 108, 114, 120, 132, 138, 144, 150, 156, 162, 174, 180, 186, 192 and 198 are even numbers,
∴ x = 33 - 20 = 13