NTSE Stage 2 SAT 2015 Question Paper

According to question
$\mathrm{a}=\mathrm{b}+\mathrm{c}-8$... (i)
$\mathrm{b}=\mathrm{a}+\mathit{c}-8$ ... (ii)
$\mathrm{c}=\mathrm{a}+\mathrm{b}-8$ ... (iii)
Solving equation (i),(ii),(iii) we get
$\mathrm{a}=\mathrm{b}=\mathrm{c}=8$
∴ The given triangle is equilateral triangle
∴ Area of equilateral triangle
$=\frac{\sqrt{3}}{4}{\left(\mathrm{side}\right)}^2=\frac{\sqrt{3}}{4}{\left(8\right)}^2=16\sqrt{3}$
∴ Option (d) is correct.