Heights and Distances Practice Test 1

Question : 38 of 40

Marks: +1, -0

The angles of elevation of the top of a tower 30 m high from two points on the level ground on its opposite sides are 30° and 60°. The distance between the two points in the nearest metres is:

40 m
$40√3$ m
$30√3$ m
All of the above
None of these

Validate

Solution:

In ΔADC,

30/x=\tan60°=√3

⇒x=30/√3

......(1)
In ΔABD,

30/y=\tan30°=1/√3

⇒y=30√3

......(2)
Adding equations (1) and (2)

x+y=30/√3+30√3

={30+90}/√3=40√3m

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