Mensuration Practice Test 3

Diagonal of the square = 12 $\sqrt{2}$
Side of the square = a

Perimeter of the square = 4 a = 2 d $\sqrt{2}$
4a = 2 ×12 $\sqrt{2}\times \sqrt{2}$
4a = 48
a = 12 cm
Radius of the circle = 6 cm
Division of the median of the triangle = 2 : 1
= 9 cm
Side of the equilateral triangle = $\frac{\sqrt{3}}{2}\mathit{a}$ = 9
a = 9 × $\frac{2}{\sqrt{3}}$
a = $6\sqrt{3}$ cm