Mensuration Practice Test 4

Volume of the parallelepiped and the cube are the same
l × b × h = ${\mathit{a}}^3$
2x × 4x × 8x = ${\mathit{a}}^3$
$64{\mathit{x}}^3$ = ${\mathit{a}}^3$
4x = a
Ratio of their surface areas
= 2(lb + bh + hl) : $6{\mathit{a}}^2$
⇒ $2\left(8{\mathit{x}}^2+32{\mathit{x}}^2+16{\mathit{x}}^2\right):6{\mathit{a}}^2$
$2\left(56{\mathit{x}}^2\right):112{\mathit{x}}^2$
$112{\mathit{x}}^2:64{\mathit{x}}^2$
112 : 64
56 : 32
7 : 4