Volumes Practice Test 3

Here, ${\mathit{a}}^3$ = 27 × 8 × 1
∴ a = 3 × 2 = 6 cm
Total surface area of the cuboid = 2 (27 × 8 + 8 × 1 + 1 × 27)
= 2 × 251 = 502 $\mathit{c}{\mathit{m}}^2$
Total surface area of the cube = 6 × 62 = 216 $\mathit{c}{\mathit{m}}^2$
Hence, required difference = 502 – 216 = 286 $\mathit{c}{\mathit{m}}^2$