RRB Group D 15-Oct-2018 Shift 1 Solved Paper

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Question : 77 of 84

Marks: +1, -0

A natural number when divided by 5,6,7 or 9 leaves a remainder of 1 in each case. What isthe smallest of all such numbers?

421
631
1261
211

Solution:

{LCM}

of 5,6,7,9

=3 \×3 \×2 \×5 \×7=630

\∴

Smallest number

=630+1=631

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