If \sin {A}=\frac{12}{13}, then the value of (\sec A+{\cosec} A)is:

RRB Group D 23-Oct-2018 Shift 3 Solved Paper

Question : 81 of 100

Marks: +1, -0

\sin {A}={12}/{13},

then the value of

(\sec A+{\cosec} A)

is:

Solution:

\sin {A}={12}/{13}, {\cosec} {A}

={1}/{\sin {A}}={13}/{12}

\cos {A}=√{1-({12}/{13})^{2}}

=√{{169-144}/{169}}={5}/{13}

\sec {A}={1}/{\cos {A}}={13}/{5}

\sec {A}+{\cosec} {A}={13}/{5}+{13}/{12}

={156+65}/{60}={221}/{60}

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