RRB Group D 3-Dec-2018 Shift 3 Solved Paper

A number is divisible by 11, if the sum of digits at odd and even places are equal or differ by a number divisible by 11 Here, the given number = 295 x 5
So, sum of digits at even place = 9 + x
Sum of digits at odd place = 2 + 5 + 5
⇒9 + x = 2 + 5 +5
x = 1 2 - 9 ⇒ x = 3