RRB Group-D Model Paper 11 with answers for online practice

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Question : 64 of 100

Marks: +1, -0

If

x+1/x

=6, then the value of

2x/{3x^2−4x+3}

is

1
$1 1/7$
1/7
3/7

Solution:

x+1/x

=6
⇒

x^2

+ 1 = 6x
Now,
=

{2x}/{3x^2−4x+3}

=

{2x}/{3(x^2+1)−4x}

=

{2x}/{3×6x−4x }

= 2x/14x
= 1/7

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