RRB Group-D Model Paper 13 with answers for online practice

Tips & Tricks Triangles= $\mathit{n}\times \frac{\mathit{n}+1}{2}\times \mathit{H}$
Where,
n= number of small triangles
H = number of ‘end to end’ horizontal lines
→ In, ∆ABC:
n= number of small triangles = 5
H = number of ‘end to end’ horizontal lines = 1 (BC)
Triangles= $5\times \frac{5+1}{2}\times 1=15$
Hence, Total triangles in ∆ABC = 15
Hence, there are 15 trianglesin the given figure.