RRB Group-D Model Paper 15 with answers for online practice

Question : 61 of 100

Marks: +1, -0

ΔABC is right angled at B. If sin A = 3/5, then find the value of tan C.

Solution:

In the given ∆ABC,

sin A = perpendicular/hypotenuse = BC/AC = 3/5
Now, cos A =

√(1 – sin^2A) = √(1 – 9/25) = √(16/25) = 4/5

⇒ tan A = sin A/cos A = (3/5) / (4/5) = 3/4
But, tan A = perpendicular/base = BC/AB
⇒ BC/AB = 3/4
Now,
tan C = AB/BC
∴ tan C = 4/3

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