Correct Answer is : Anhydrous ZnCl2 / HCl

RRB Group-D Model Paper 17 with answers for online practice

Question : 63 of 100

Marks: +1, -0

Lucas reagent is

Anhydrous $CuCl_2$ / HCl
Anhydrous $ZnCl_2$ / HCl
Anhydrous $CuCl_2$ / $H_2SO_4$
Anhydrous $ZnCl_2$ / $H_2SO_4$

Solution:

Concept:
Lucas reagent is a solution of anhydrous

ZnCl_2

and concentrated HCL
It is used to distinguish alcohol molecule (primary/secondary alcohol) of low molecular weight
Explanation:
From the above explanation, we can see that Lucas reagent is a solution of Anhydrous

ZnCl_2

and HCl

Go to Question:

Prev Question

Next Question