RRB Group D Model Paper 9 with solutions

© examsiri.com

Question : 89 of 100

Marks: +1, -0

If cos θ =

3 /5

, then the value of sin θ. sec θ. tan θ is

$9 /16$
$16 /9$
$3 /4$
$4/ 3$

Solution:

(2) Since, cos θ =

3 /5

, sosecθ =

5/3

and
tanθ =

√{sec^2θ-1}

=

√{(5/3)^2-1}=4/3

Therefore,
sinθ .secθ .tanθ =

{sinθ}/{cosθ}

x tanθ
=

tan^2θ=(4/3)^2

=

16 /9

© examsiri.com

Go to Question:

Prev Question

Next Question