RRB NTPC 18 January 2017 Paper

Question : 119 of 120

Marks: +1, -0

Find the value of k in
$26/21$ : $24/9$ ::k: $14/13$

Solution:

(3)

\ { 20 }/ { 21 } : \ { 24 }/ { 9 } : \ { k } : \ { 14 } /{ 13 }

\ { 26 } /{ 21 } \× \ { 9 }/ { 24 } = \ { k } \× \ { 13 } /{ 14 }

\ { k } = \ { 26 } /{ 21 } \× \ { 9 } /{ 24 } \× \ { 14 }/ { 13 } = \ { 1 } /{ 2 }

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