RRB NTPC 29 April 2016 Paper

Question : 70 of 100

Marks: +1, -0

On dividing 15

y^3

– 30

y^2

+ 12y −12 by 3y – 6 , the remainder is :

Solution:

(4) For dividing

15 y ^ { 3 } - 30 y ^ { 2 } + 12 y -

12 by

3 y - 6

Put

3 y = 6

y = 2

in the equation

\⇒ 15 y \( y ^ { 2 } ) - 30 y ^ { 2 } + 12 y - 12

\⇒ 30 y ^ { 2 } - 30 y ^ { 2 } + 12 ( 2 ) - 12

= 12

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