RRB NTPC Prelims Model Paper 2 with solutions

Question : 49 of 101

Marks: +1, -0

ABC is a triangle and the sides AB, BC and CA are produced to E, F and G, respectively. If ∠CBE = ∠ACF = 130° then the value of ∠GAB is

Solution:

∠ CBE = 130°
∴ ∠ ABC = 180° - 130° = 50°
∠ ACF = 130°
∴ ∠ ACB = 180°- 130° = 50°

∴ ∠ BAC

= 180° - 50° =50°= 80°

∴∠ GAB = 180° -80° = 100°

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