RRB NTPC Prelims Model Paper 2 with solutions

Question : 65 of 101

Marks: +1, -0

If P:Q = 3:4, Q:R = 5:7 and R:S = 8:9, then P:S would be:

Solution:

P /S=P/Q× Q/ R×R/S

3/4×5/7×8/9= 10/21

Thus, P : S = 10 : 21

Go to Question:

Prev Question

Next Question