SSC CGL 10 Jun 2019 Shift 2 Paper

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Question : 66 of 100

Marks: +1, -0

In

\Δ {\ABC}

, AD is median and

\ {\G}

is the point on

\ {\AD}

such that

\ {\AG}: \ {\GD}=2: 1 .

Then

\ {\ar}(\Δ {\ABG}): \ {\ar}(\Δ {\ABC})

is equal to:

1 : 5
1 : 4
1 : 6
1 : 3

Solution:

We know , if G is the centroid of ΔABC ar

\Δ {\ABG}:

ar

\Δ {\BGC}:

ar

\Δ {\AGC}=1: 1: 1

\ {\Ar(\Δ\ABG)}/{\Ar(\Δ\ABC)}=\ {1}/{3}

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