SSC CGL 12 Aug 2017 Shift 1 Paper

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Question : 53 of 100

Marks: +1, -0

In the given figure,

\ABCD

is a rectangle.

F

is a point on

\AB

and

\CE

is drawn perpendicular to

\DF

If

\CE=60 {\cm}

and

\DF=40 {\cm}

then what is the area (in

{\cm}^{2}

) of the rectangle

\ABCD ?

1200
1800
2400
2800

Solution:

Area of rectangle

\ABCD

=C E × D F=60× 40

=2400 {\cm}^{2}

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