What is the value of \sin (-\\pi / 3)+\cos (-\pi / 6) ?

SSC CGL 12 Aug 2017 Shift 1 Paper

Question : 69 of 100

Marks: +1, -0

What is the value of

\sin (-\π / 3)+\cos (-π / 6) ?

Solution:

\sin (-\π / 3)+\cos (-π / 6)

=-\sin {180°}/{3}+\cos {180°}/{6}

=-\sin 60°+\cos 30°

= -{√{3}}/{2}+ {\√{3}}/{2}=0

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