SSC CGL 12 Jun 2019 Shift 2 Paper

Question : 59 of 100

Marks: +1, -0

The radii of two circular faces of the frustum of a cone of height 10.5 cm are 5 cm and 3 cm respectively.
What is its volume in cm

^{3}

(\π=22/7)

Solution:

Volume

=\ {\πh}/{3}\ (r^{2}+R^{2}+r R\ )

=\ {22}/{7} \×\ {10.5}/{3}(9+25+15)

=539 \ {\cm}^{3}

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