SSC CGL 12 Jun 2019 Shift 2 Paper

Question : 61 of 100

Marks: +1, -0

In ΔABC, P is a point on BC such that BP : PC = 3 : 4and Q is the midpoint of BP. Then ar(ΔABQ) : ar (ΔABC) is equal

Solution:

since

\Δ {\ABC}

and

\Δ{\ABQ}

are of same height.

\ {\Ar \Δ\ABQ}/{\Ar \Δ\ABC}=\ {B Q}/{B C}=\ {3}/{14}

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