SSC CGL 12 Jun 2019 Shift 2 Paper

Question : 67 of 100

Marks: +1, -0

ΔABC ~ ΔRQP and PQ = 10cm, QR = 12cm and RP = 18cm. If ar (ΔABC) : ar (ΔPQR) =

4/9

, then AB is equal to:

Solution:

\ { {\ar}(\Δ\PQR)}/{\ {\ar}(\Δ\ABC)}=\ {9}/{4}=\ (\ {R Q}/{A B}\ )^{2}

\ {12}/{A B}=\ {3}/{2}

\⇒A B=8

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