SSC CGL 13 Jun 2019 Shift 1 Paper

Question : 69 of 100

Marks: +1, -0

In ΔABC, P is a point on BC such that BP : PC = 4 : 5 and Q is the mid point of BP.
Then ar (ΔABQ) : ar (ΔABC) is equal to:

Solution:

\ {\ {\ar}(\ABQ)}/{\ {\ar}(\ABC)}=\ {2}/{9}

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