SSC CGL 19 Oct 2014 Shift 2 Paper

Question : 101 of 200

Marks: +1, -0

For any integral value of n,

3^{2n}

+ 9n + 5 when divided by 3 will leave the remainder

Solution:

Expression =

3^{2n}

+ 9n + 5
=

3^{2n}

+ 9n + 3 + 2
= 3 (

3^{2n-1}

+ 3n + 1 ) + 2
Clearly, remainder = 2

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