SSC CGL 26 Oct 2014 Shift 2 Paper

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Question : 140 of 200

Marks: +1, -0

The value of

1/√2

sin

π/6

cos

π/4

- cot

π/3

sec

π/6

+

{5tanπ/4}/{12sinπ/2}

is equal to

0
1
2
$3/2$

Solution:

Expression =

1/√2

sin

π/6

cos

π/4

- cot

π/3

sec

π/6

+

{5tanπ/4}/{12sinπ/2}

=

1/√2 × 1/2 × 1/√2

-

1/√3×2/√3+{5×1}/{12×1}

=

1/4-2/3+5/{12}

=

{3-8+5}/{12}

= 0

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