If x^4+x^2 y^2+y^4=21 and x^2+x y+y^2=7, then the value of (\frac{1}{x^2}+\frac{1}{y^2}) is:

SSC CGL 3 Mar 2020 Shift 2 Paper

Question : 57 of 75

Marks: +1, -0

x^4+x^2 y^2+y^4=21

and

x^2+x y+y^2=7

, then the value of

(\;{1}/{x^2}+\;{1}/{y^2})

is:

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