SSC CGL 3 Mar 2020 Shift 2 Paper

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Question : 66 of 75

Marks: +1, -0

In

△ {\ABC}, {\AB}= {\AC}

and

{\AL}

is perpendicular to

{\BC}

at

{\L}

. In

△ {\DEF}, {\DE}= {\DF}

and

{\DM}

is perpendicular to

{\EF}

at

{\M}

. If (area of

△ {\ABC}):(

are of

△ {\DEF})=9: 25

and

∠ {\BAC}=∠ {\EDF}

, then

\;{ {\DM}+ {\AL}}/{ {\DM}- {\AL}}

is equal to:

3
5
6
4

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