SSC CGL 3 Sep 2016 Paper

Question : 67 of 100

Marks: +1, -0

AB is a diameter of a circle. C is a point on the tangent drawn at A. If AB = 8 cm and AC = 6 cm, then the length of BC is :

Solution:

AB ⊥ AC
∴ ∠BAC = 90°
∴ BC =

√{AB^2+AC^2}

√{8^2+6^2}

√{64+36}

√{100}

= 10 cm

Go to Question:

Prev Question

Next Question