SSC CGL 30 Aug 2015 Paper

Question : 101 of 200

Marks: +1, -0

A train travels 500 m in first minute. In the next 4 minutes, it travels in each minute 125 m more than that in the previous minute. The average speed per hour of the train during those 5 minutes will be

30 km/hr
45 km/hr
50 km/hr
55 km/hr

Validate

Solution:

Total distance covered by train in 5 minutes
= (500 + 625 + 750 + 875 + 1000) metre = 3750 metre
= 3.75 km.
Time = 5 minutes =

5/{60}

hour
=

1/{12}

hour
Speed of train =

{\Distance}/{\Time}

({3.75}/{1/{12}})

kmph
= (3.75 × 12) kmph
= 45 kmph

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