SSC CGL 30 Aug 2015 Paper

Question : 114 of 200

Marks: +1, -0

ΔABC is an isosceles triangle with AB = AC = 10 cm, AD = 8 cm is the median on BC from A. The length of BC is

Solution:

D, is the mid–point of BC.
AB = AC = 10 cm.
AD ⊥ BC
From ΔABD,
BD =

√{AB^2-AD^2}

√{10^2-8^2}

√{100-64}

√{36}

= 6 cm
∴ BC = 2 BD = 2 × 6 = 12 cm.

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