SSC CGL 30 Aug 2015 Paper

Question : 117 of 200

Marks: +1, -0

In a circle with centre O, AB and CD are two diameters perpendicular to each other. The length of chord AC is

Solution:

OA = OB = OC =

{AB}/2

∴ AC =

√{OA^2+OC^2}

√{({AB}/2)^2+({AB}/2)^2}

√{{AB^2+AB^2}/4}

√{{AB^2}/2}

{AB}/√2

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